replace

Unlike Bourne Again Shell (bash), POSIX shell does not have a native find/replace function for replacing one occurrence of a pattern in a given string with another. Below is an implementation written in native POSIX shell that is:

• Faster than piping to awk, sed, perl, python, ruby, or other langauge

• Compatible with bash and all other POSIX-compliant shells

• Optimized to use ${parameter/pattern[/string]} when bash is detected

 1 #!/bin/sh
 2 if [ "$BASH_VERSION" ]; then
 3     replace() # $var_to_get $find $replace [$var_to_set]
 4     {
 5         eval ${4:-$1}=\"\${$1/\$2${3:+/\$3}}\"
 6     }
 7 else
 8     # NB: On FreeBSD, sh(1) runs this faster than bash(1) runs the above
 9     replace() # $var_to_get $find $replace [$var_to_set]
10     {
11         eval local __left= __right=\"\$$1\" || return
12         case "$__right" in *$2*)
13             __left="${__right%%$2*}$3"
14             __right="${__right#*$2}"
15         esac
16         eval ${4:-$1}=\"\$__left\$__right\"
17     }
18 fi
19 eval echo \"before=[\$$1]\"
20 replace "$@"
21 eval echo \" after=[\$${4:-$1}]\"